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How does Isildur fit into RoP, Hobbit and LOTR timelines?

Solution
You might be confused a bit by Jackson's films and the Rings of Power show -- since Isildur was in Jackson's Lord of the Rings, but his scene (fighting Sauron and ending up with the One Ring) was way (way) before Bilbo's time. . .

. . . and the Rings of Power show is purposely messing with Tolkien's timeline. In Tolkien's timeline, the rings were forged way (way) before Isildur took the One from Sauron's hand. Here's some dates from JRRT's Tale of Years.

Second Age

Year (C.) 1,590 -- The Three Rings are completed in Eregion

Year 3,441 -- Isildur takes the One from Sauron

I'd do the math, but I only have 🐾 🐾 and that's a lot of years in between...
Isildur is a man of Numenor and much like his descendant, Aragorn, was blessed with a long life. I don't understand what you mean by him being present during the war of the rings. Isildur, from what I know, died some times after Sauron was temporarily defeated after Dagorlad.(where Isildur manages to come in the possession of The One Ring.)
But to sum it up, men of the west and the elves defeat Sauron and Isildur gets the ring, Isildur dies and the rings is lost, Gollum finds it, the events of The Hobbit happens and the LoTR happens.
 
You might be confused a bit by Jackson's films and the Rings of Power show -- since Isildur was in Jackson's Lord of the Rings, but his scene (fighting Sauron and ending up with the One Ring) was way (way) before Bilbo's time. . .

. . . and the Rings of Power show is purposely messing with Tolkien's timeline. In Tolkien's timeline, the rings were forged way (way) before Isildur took the One from Sauron's hand. Here's some dates from JRRT's Tale of Years.

Second Age

Year (C.) 1,590 -- The Three Rings are completed in Eregion

Year 3,441 -- Isildur takes the One from Sauron

I'd do the math, but I only have 🐾 🐾 and that's a lot of years in between!

Third Age

Year 2 -- Isildur is slain

Year 2,941 -- Bilbo finds the One Ring

This math seems easier, but I'm still not doing it :)
 
Solution
Rookie 😄
Or "smart"-phone user? I have the "calculator" thingy in my Windows task toolbar, and on my scree it's about the size of one of those mobiles. Though there should be a Windows version for mobiles ... 🤔
 
Or "smart"-phone user? I have the "calculator" thingy in my Windows task toolbar, and on my scree it's about the size of one of those mobiles. Though there should be a Windows version for mobiles ... 🤔
Or one could just grab a pencil and paper....😉
 
Or one could just grab a pencil and paper....
This is for old folks.
Younger folks have 'tools' creating a decline in abilities.
Youngest folks aren't even taught how to do math any more. 😆
They all have 'devices.'
(Have you seen them try to 'count back change' at a register, when older folks hand them real money?)
 
Here's some dates from JRRT's Tale of Years.

@LandSeahorse - Tale Of Years Elthir refers to here is APPENDIX B in the back of most Tolkien Lord of the Rings books. (If you've a 3-volume set, probably at back of the 3rd volume.)

Very useful.
Even for people with paws like @Elthir - though I suspect he has it catmerized by now.


p.s. - don't hesitate to introduce yourself to the family in the new members thread. We're very helpful (and easily side-tracked.) 😁

New Members Thread is here: https://thetolkien.forum/forums/new-members.58/
 
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This is for old folks.
Younger folks have 'tools' creating a decline in abilities.
Youngest folks aren't even taught how to do math any more. 😆
They all have 'devices.'
(Have you seen them try to 'count back change' at a register, when older folks hand them real money?)
Not just younger folks (altho' they do comprise a majority of the "device dependent").
Ask most anyone you know to add 2/3 and 3/5 (2/3 + 3/5) without benefit of any "calculating" device, and watch the sweat break out along with a slightly panicky expression. Even more fun, ask them to do it their head.
 
watch the sweat break out along with a slightly panicky expression. Even more fun, ask them to do it their head.
Yeah, I remember when I knew how to extract square roots.
(But over time, all my roots have become a bit rounded.)
 
By the way, I should have noted that the Second Age ended with year 3,441 (Isildur takes the One), and so, Third Age 2 (Isildur being slain) is not long after. In The Tale of Years, entries for the Third Age begin with year 2 -- which possibly means that too many clocks were destroyed in SA 3,441.

And I would do the math in my head. . . if I wanted to, which I still don't.

🐾
 
Frodo stopped doing math
after he carried the one.

What's the meaning of carry the one? I heard this phrase at a podcast.  The following is their conversation. Leah: You got it and they asked Prince  Rupert who was the cousin


AHEM
 
That's 10/15 + 9/15 = 19/15, or 1.2666... in infinite decimal notation.
Wazza problm? 🤨
Most people have a "problem" (pun intended 😄) with fractions (even using a calculator they may not know how to enter fractions).
Don't ask me why, but they do; second only to their fear of doing long division (again, without a calculator)
I chose those fractions at random. When 19/15 came up as the answer I didn't bother to convert to a decimal, so I didn't know it was repeating, which is, in any case, irrelevant to my assertion.

BTW, for anyone who has the time you may want to read this short story (and it's pretty short) by Isaac Asimov: The Feeling of Power
 
When 19/15 came up as the answer I didn't bother to convert to a decimal, so I didn't know it was repeating, which is, in any case, irrelevant to my assertion.
Perhaps this is helpful for some people.
The result is 1 + 4/15;
4/15 = 3/15 + 1/15;
3/15 = 1/5 = 0.2;
1/15 is 1/3 of 0.2 = 0.0666...
 
Covert fractions to decimals: divide the numerator (top number) by the denominator (bottom) number, and ....Ta-da!
(And to as many places as you like....😉)
 
You mean square root of 58.6600375042 ?
Actually, no. 3441 is the SQUARE of 58.6600375042. Or said differently, is "58.6600375042 squared."

58.6600375042 is the "square root" of 3441. The suare root of 58.6600375042 would be the number which multiplied by itself would equal 58.6600375042, so would be much smaller.

(But I aint' gonna work it out, though it is the square of 7.658984103926578, which is its square root.)
 

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